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2 years ago

One half of the number n increased by 10 is the

Mathematics

1 answer:

gtnhenbr [62]2 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{n}{2} +10=2n-4$

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A new coffee shop is opening and plans to sell cups of coffee at $4 each. It costs $3 to make each cup of coffee, and the shop n

never [62]

Answer:

the answer is b

Step-by-step explanation:

6 0

2 years ago

Somebody please help me answer this

Inga [223]

-2x+4 I am pretty sure

8 0

3 years ago

In Japan. traditionally it was believed that if you folded 1,000 origami cranes, your wish would come true. For a party, Emika i

vfiekz [6]

Answer:

Step-by-step explanation:

Remark

Interesting detail.

Origami Paper is square -- perfectly.

So the properties listed will be related to a square.

Givens

Area = 35 in^2

Formulas

Area = s^2 where s is the length of 1 side.

Perimeter = 4s

Solution

s^2 = 35 Take the square root of both sides.

√s^2 = √35

s = 5.91

<u>Perimeter = 4s</u>

s = 5.91

Perimeter = 4*5.91

Perimeter = 23.66

The way the question is worded, the answer you should submit is

Perimeter = 4 * √35

4 0

2 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

How many solutions does 5x-y=2 5x-y=-2 have?

alekssr [168]

Answer:

No Solution.

Step-by-step explanation:

5x-y=2

5x-y=-2

-------------

-(5x-y)=-2

5x-y=-2

----------------

-5x+y=-2

5x-y=-2

-------------

0=-4

no solution

7 0

3 years ago