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Novosadov [1.4K]
3 years ago
10

Find the slope Plz help

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

6

-

5

Step-by-step explanation:

You can do there are multiple ways but the easiest is rise over run so

so -4 to 2 is 6 and -2 to 3 is 5 so the answer is

6

--

5

You can also do the much harder way of

Y2-Y1   (-2,-4)     2-(-4)    6

---------    x  y       --------= --

X2-X1    (3,2)      3-(-2)    5

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What is the side length of a cube with volume 343 in squared?
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Hi there!

The formula for a square is V = s^3. Using this formula, we can plug in the volume and solve for s.

WORK:
343 = s^3
s = 7

ANSWER:
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Hope this helps!! :)
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3 years ago
a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t
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Answer:

The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

Step-by-step explanation:

Given:

Circumference of the circle = 2\pi r

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}

Now we know that;

side of the square= diameter of the circle

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Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}

But \frac{dr}{dt} =\frac{3}{\pi}

So we get;

\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\  in/sec

Hence The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

5 0
3 years ago
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