Answer:
see below
Step-by-step explanation:
The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.
The line of symmetry is the value of x that makes the squared term zero. Here, that is x=5 for all equations.
<u>y=2/3(x-5)^2</u>: A, D
<u>y=1/2(x-5)^2</u>: A, D
<u>y=3/4(x-5)^2</u>: A, D
<u>y=-4(x-5)^2</u>: B, D
That is true because you are still dividing x by three either way
Im not too sure but I think its 4.6,because 1 in :.5 mile. As a whole, .5 can go into 2, 4 times, then whats left over also gets divided into .6. Add those together and youll get 4.6
Answer:
268+v2)3+p=8 =p=−3v2−796
Step-by-step explanation:
Let's solve for p.
(268+v2)(3)+p=8
Step 1: Add -804 to both sides.
3v2+p+804+−804=8+−804
3v2+p=−796
Step 2: Add -3v^2 to both sides.
3v2+p+−3v2=−796+−3v2
p=−3v2−796
<em><u>Hope this helps.</u></em>
Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
