Answer:
add me on snap kharding1805 and I will add you back
Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
AD is perpendicular to BC so slope Ad = -1/slope of BC
Slope of BC = (2 - (-1)) / (- 6- 3) = 3 / -9 = -1/3
So slope of AD = -1 / (-1/3) = -3/-1 = 3 Answer
Answer:
36,170.21276595745 (I did this on a calculator.)
Step-by-step explanation:
17000/47 = 361.7021276595745
361.7021276595745 x 100 = 36,170.21276595745
Your total answer is 36,170.21276595745.
The answer is option d) T(Q+6.5) = R
