Given:
15. 
17. 
19. 
To find:
The values of the given logarithms by using the properties of logarithms.
Solution:
15. We have,

Using property of logarithms, we get
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is 1.
17. We have,

Using properties of logarithms, we get
![[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D-%5Clog_a%5Cdfrac%7Bn%7D%7Bm%7D%5D)
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is -1.
19. We have,

Using property of logarithms, we get
![[\because a^{\log_ax}=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B%5Clog_ax%7D%3Dx%5D)
Therefore, the value of
is 100.
The answer is A, because 43 of the flights were from UA and were on time, this is out of a whole of 87 flights.
Answer:
(-2, 2)
Step-by-step explanation:
<u>Given:</u>
- Point A is at (2, -8) and point C is at (-4, 7)
<u>Difference of coordinates:</u>
- Δx = 2 - (-4) = 6
- Δy = - 8 - 7 = - 15
<u>The ratio of AB to AC is 2:1. So:</u>
- AB = 2*AC/3 and BC = AC/3
<u>Then coordinates of point B should be 2/3 from the point A:</u>
- x = 2- 6*2/3 = 2 - 4 = -2
- y = - 8 - (-15)*2/3 = -8 + 10 = 2
So point B has coordinates of (-2, 2)
9(2) + 2(y) = 50. solve for y. 32=2y, y=16. It is 16 meters long.
It is
(3-x)^2
i made sure it correct this time