Find the total cost of a $39 pizza order if you leave a 15% tip.

Imagine a population of birds with an initial size of 100, a per-capita birth rate of 2, and a per-capita death rate of 1 per ye

Soloha48 [4]

Answer:

3200

Step-by-step explanation:

Given that:

The initial population of birds $N_0$ = 100

The time duration t = 5 years

Growth rate (r) = (Birth - Death) rate

= 2 - 1

= 1 / year

∴

using the discrete-time form:

$N_t = N_o (1 + r )^t$

$N_t = 100 (1 + 1 )^5$

$N_t = 100 (2 )^5$

$N_t = 100 \times 32$

$N_t = 3200$

8 0

2 years ago

Jane buys 220 milliliters of lotion for $7.50. She divides the lotion evenlyamount 5 smaller bottles. How many liters are in eac

KonstantinChe [14]

220 (divide sign) 5 = 44ml (change it to liters) 0.044 (move the decimal from 44.0 their by two spots so it would be 0.044)

5 0

3 years ago

Read 2 more answers

PLZZ Help me algebra 2.

Kipish [7]

Answer:

32

Step-by-step explanation:

7 0

3 years ago

We did it! We made it to the end! thanks for helping everyone!

Alecsey [184]

Answer:

12.058

Step-by-step explanation:

You steal one "count" from the 8, and move it to the 7 so you have 12.0587, instead of 12.0578. Then, you are able to take off the 7 from the back.

4 0

2 years ago

Read 2 more answers

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0

3 years ago