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Mrrafil [7]
2 years ago
7

Les municipalités de Sainte-Julie,

Mathematics
2 answers:
photoshop1234 [79]2 years ago
7 0
Can you help me with this question please

Ludmilka [50]2 years ago
6 0

Answer:

CNC app BC we can we can MN we all at can we can we do all we can we go we go we cannot GL can see VM we BM

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Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
3 years ago
A mechanic used 49 quarts of oil in 7 cars. At this rate, how much oil would he use to change the oil in 17 cars?
Karo-lina-s [1.5K]

Answer:

Each car used 7 quarts of oil. So 7 cars would use 7×17 quarts which would be 119 quarts.

8 0
2 years ago
I need help on this for real
saveliy_v [14]

Answer:

x < 3

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

8 0
2 years ago
Easy math please help
insens350 [35]

1) False

Adjacent angles must share a common side/ray.

2) B and D

Adjacent angles are those that are directly next to each other and share a common side.

3) C

Angles 1 and 2 are congruent. Angles 3 and 4 are congruent. Both of these pairs have angles that are opposite each other.

4) B

Angles 1 and 2 add up to 180. Angles 3 and 4 add up to 180. Both of these pairs of angles are supplementary.

5) A

These angles are directly next to each other and share a common side.

Hope this helps!! :)

4 0
2 years ago
Given AE and BD bisect each other at point c, which congruence theorem would you use to prove triangle ABC =~ triangle EDC ?
baherus [9]
The answer is C (SAS)

Explanation:
AC = EC
BC = DC
angle ACB = angle DCE (Vertically Opposite Angles)
Therefore, the triangles are congruent by the Side-Angle-Side congruency
4 0
3 years ago
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