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juin [17]
3 years ago
14

Please help soon because I really need to finish my last homework question quickly

Mathematics
1 answer:
erica [24]3 years ago
7 0

Answer:

what is the question? May you please show us

Step-by-step explanation:

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does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
4 years ago
172% of 50 is what number?
Likurg_2 [28]

Answer:

172% of 50 means 172÷100 multiplied by 50 will give you 86

6 0
2 years ago
Read 2 more answers
Abby is surveying people in the city about their interest in a new shopping mall. She found that 180 people, or 37.5% of those s
Harlamova29_29 [7]

Step-by-step explanation:

37.5% = 180people

100% = 180/37.5 x 100 = 480

answer: 480 people

Topic: percentage

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!

6 0
3 years ago
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
4 years ago
Create a linear equation in the slope-intercept form that contains points (2,−8) and (6,−4) .
nadezda [96]

Answer:

y = x - 10

Step-by-step explanation:

Find the slope:

-4 - (-8) ÷ 6 - 2

-4 + 8 ÷ 6 - 2

4 ÷ 4

= 1

Substitute into the slope-intercept equation:

y = mx + b

Let's use the first coordinate (2,-8) for the x and y values

m = 1

-8 = 1(2) + b

-8 = 2 + b

-2    -2

-10 = b

Write equation:

y = 1x -10 or y = x -10

3 0
3 years ago
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