Answer:
common numerator and denomanator
Step-by-step explanation:
In this item, we are informed that the order of the entries does not matter in determination the number of ways in which the Archie can choose for his party. Because the arrangement or order is not important, this type of problem uses the concept of COMBINATION.
The equation for combination is,
nCr = n!/((n - r)!(r!))
nCr is read as "combination of n taken r".
Substituting the known values to the equation,
15C6 = 15! / ((15 - 6)!(6!))
= 5005
Hence, there are 5005 ways in which Archee can choose the 6 entrees for his party.
The correct answer is G. Integers include whole numbers and natural numbers.
Explanation:
The graph presented shows the relationship between different sets of numbers. In this graph, the second most general category is integers, and this covers or includes two smaller categories which are whole numbers and natural numbers. This means the whole and natural numbers are part of integers.
Indeed, integers include numbers such as 10, 256, or -6 because these can be expressed without using fractions or decimals. Also, this category includes whole or non-decimal numbers, as well as natural numbers, which are positive whole numbers such as 36 or 1546. According to this, the correct answer is G.
Answer:
0
Step-by-step explanation:
Simplifying
-7(x + -2) + 1 = 15 + -7x
Reorder the terms:
-7(-2 + x) + 1 = 15 + -7x
(-2 * -7 + x * -7) + 1 = 15 + -7x
(14 + -7x) + 1 = 15 + -7x
Reorder the terms:
14 + 1 + -7x = 15 + -7x
Combine like terms: 14 + 1 = 15
15 + -7x = 15 + -7x
Add '-15' to each side of the equation.
15 + -15 + -7x = 15 + -15 + -7x
Combine like terms: 15 + -15 = 0
0 + -7x = 15 + -15 + -7x
-7x = 15 + -15 + -7x
Combine like terms: 15 + -15 = 0
-7x = 0 + -7x
-7x = -7x
Add '7x' to each side of the equation.
-7x + 7x = -7x + 7x
Combine like terms: -7x + 7x = 0
0 = -7x + 7x
Combine like terms: -7x + 7x = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
Answer:
a) P (0 defective component) = 0.5
P( 1 defective component ) = 0.35
P( 2 defective component ) = 0.15
b) P( 0 ) = 0
p ( 1 ) = 1
p ( 2 ) = 0.33
Step-by-step explanation:
p( no defective ) = 0.5
p( 1 is defective ) = 0.35
p( 2 is defective ) = 0.15
Given that 2 components are selected at random
<u>a) Given that neither component is defective </u>
Probability of 0 defective component = 0.5
P( 1 defective component ) = 0.35
P( 2 defective component ) = 0.15
<u>b) Given that one of the two tested component is defective </u>
P( 0 defective ) = 0
P( 1 defective ) = P ( 
) = p( x = 1 ) / 1 - P ( x = 0 )
= ( 0.5 )^1 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^1
= 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 = 1
p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )
= ( 0.5 )^2 ( 0.5 )^0 / 1 - ( 0.5)^0 (0.5)^2
= 0.25 / 0.75 = 0.33
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