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Anna007 [38]
3 years ago
6

This question is designed to be answered with a calculator.

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

0.451

Step-by-step explanation:

When you do cos^-1 0.9 ~ .451

You can’t add pi because you have an interval.

Hope this helps :)

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gary mixes a solution using two types of concentration of sale: .70 gallons of 5% and .30 gallons of 22% salt. what is the conce
wolverine [178]

Answer:

10.1%

Step-by-step explanation:

The first thing we should do is calculate the total volume of the solution when mixing them would be:

0.7 + 0.3 = 1

Now, we have that the resulting concentration (x) would be equal to the sum of the multiplications between the volumes and the concentrations to be mixed, as follows:

x * 1 = 0.7 * 0.05 + 0.3 * 0.22

x = 0.035 + 0.066

x = 0.101

That is, the concentration of the resulting mixture would be 10.1% (0.101 * 100)

5 0
3 years ago
2s+4=5(−4−2s)2, s, plus, 4, equals, 5, left parenthesis, minus, 4, minus, 2, s, right parenthesis
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S= -2 and i need 20 words so ima spam lol sjdjdjfjcjchchf
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3 years ago
What is the x-coordinate of point B?<br> A<br> -1<br> B<br> - 4<br> С<br> 1<br> D<br> 4
Dmitry_Shevchenko [17]
The x-coordinate would be -4 which would be answer choice B. This is the reason bc when you look at a graph it goes from x to y same as the alphabet
5 0
3 years ago
Read 2 more answers
Which expression has a value of StartFraction 1 Over 36 EndFraction? (StartFraction 1 Over 108 EndFraction) cubed (StartFraction
IrinaVladis [17]

Answer:

(1/6)^2

Step-by-step explanation:

We want to find the fraction that is equivalent to 1/36.

Let us look at each of them individually:

a. (\frac{1}{108})^3 = \frac{1}{1259712}

b. (\frac{1}{9})^4 =  \frac{1}{6561}

c. (\frac{1}{6})^2 =  \frac{1}{36}

d. (\frac{1}{5})^2 = \frac{1}{25}

Therefore, the correct answer is c.

4 0
3 years ago
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−7x−6y=2<br> 7x+4y=−6<br> solve for x and y
ikadub [295]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:x=-2,\:y=2}

Step-by-step explanation:

\begin{bmatrix}-7x-6y=2\\ 7x+4y=-6\end{bmatrix}

\mathrm{Substitute\:}x=-\frac{2+6y}{7}

\begin{bmatrix}7\left(-\frac{2+6y}{7}\right)+4y=-6\end{bmatrix}

\begin{bmatrix}-2-2y=-6\end{bmatrix}

\mathrm{For\:}x=-\frac{2+6y}{7}

\mathrm{Substitute\:}y=2

x=-\frac{2+6\cdot \:2}{7}\\\\x=-2

5 0
2 years ago
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