Find the area of this figure Show work, please
1 answer:
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-3+3x=-2(x+1)
First: I will get rid of the bracket:
-3+3x=-2x-2
Now, all the x goes to the left side, all the numbers without x to the right side:
3x+2x=-2+3
we add up"
5x=1
divide by 5:
-3+3x=-2x-2
Now, all the x goes to the left side, all the numbers without x to the right side:
3x+2x=-2+3
we add up"
5x=1
divide by 5:
Answer:
Step-by-step explanation:
Hello!
Data
Year/Firefighters
2000: 20
2001: 18
2002: 23
2003: 30
2004: 20
2005: 12
2006: 24
2007: 9
2008: 25
2009: 15
2010: 8
2011: 11
2012: 15
2013: 34
<u>Common measures of variation</u>
<u>Variance</u>
S²=
∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34
∑X= 264
∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²
∑X²= 5770
n= 14
S²=
S²= 60.90
<u>Standard deviation</u>
The standard deviation is the square root of the variance
S= √S²= √60.90= 7.80
<u>Coefficient of variation</u>
Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.
C.V.= *100 =
*100= 41.36%
The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.
X[bar]= ∑X/n= 264/14= 18.86
<u>Range</u>
In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.
R= Xmax - Xmin= 34 - 8= 26
Xmax= 34
Xmin= 8
<u>Inter Quartile Range</u>
Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.
IQR= C₃ - C₁= 23.5 - 11.5 = 12
Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.
Pos1: n/4= 14/4= 3.5
The first quantile is the number between position 3 and position 4
8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34
C₁= (11+12)/2= 11.5
Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.
Pos3: n*3/4= 14*3/4= 10.5
The third Quantile is between position 10 and 11
8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34
C₃= (23+24)/2= 23.5
The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.
I hope it helps!
Answer:
The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.
Step-by-step explanation:
The given equation is
Where Y is the annual growth rate of a certain country's population and x is the number of years after 1900.
Difference between 1950 and 1900 is 50.
Put x=50 in the given equation.
Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.
Difference between 1988 and 1900 is 88.
Put x=88 in the given equation.
Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.
Difference between 2010 and 1900 is 110.
Put x=110 in the given equation.
Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.