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3 years ago

Trayvon has a mug shaped like a hemisphere. Its diameter is 18 cm. To the nearest hundredth, what is the capacity of her mug?

Mathematics

1 answer:

bulgar [2K]3 years ago

6 0

Answer:

The capacity of the mug is 1,527.43 cm^3

Step-by-step explanation:

In this question, we are asked to calculate the capacity of the hemisphere. This is same as calculating the volume of the hemisphere.

A hemisphere is a sharpe which is half a sphere. Meaning to get a hemisphere, we shall be diving a sphere into 2.

Mathematically, the volume of a hemisphere V = 2/3 * π * r^3

Since D = 18cm , r = D/2 = 18cm/2 = 9 cm

The volume V is thus = 2/3 * 22/7 * 9^3

V = 1,527.428 cm^ 3

To the nearest hundredth,

V = 1,527.43 cm^3

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Answer:

1810

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3 years ago

7x + 8y = 25 9x + 10y =35 elimination method please

djverab [1.8K]

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3 0

2 years ago

Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the

iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are $\frac{10\sqrt{2} }{3}$

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C = -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = $\frac{10\sqrt{2} }{3}$

From B = $\frac{10\sqrt{2} }{3}$

From C = $\frac{10\sqrt{2} }{3}$

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3 years ago

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elena55 [62]

Answer:

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Step-by-step explanation:

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3 years ago

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ANEK [815]

Answer:

Hey there!

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Let me know if this helps :)

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3 years ago