Answer:
158.4 pounds
Step-by-step explanation:
first find the volume of the tank
![V = 30 \times 30 \times 80](https://tex.z-dn.net/?f=V%20%3D%2030%20%5Ctimes%2030%20%5Ctimes%2080)
![V = 72000 cm^3](https://tex.z-dn.net/?f=V%20%3D%2072000%20cm%5E3)
to convert this to m^3 we know that 1m = 100cm
![V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3](https://tex.z-dn.net/?f=V%20%3D%2072000%20cm%5E3%20%5Ctimes%20%5Cleft%28%5Cdfrac%7B1%5C%2C%5Ctext%7Bm%7D%7D%7B100%5C%2C%5Ctext%7Bcm%7D%7D%5Cright%29%5E3)
![V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)](https://tex.z-dn.net/?f=V%20%3D%2072000%20cm%5E3%20%5Ctimes%20%5Cleft%28%5Cdfrac%7B1%5C%2C%5Ctext%7Bm%7D%5E3%7D%7B100%5E3%5C%2C%5Ctext%7Bcm%7D%5E3%7D%5Cright%29)
the cm^3 cancel out.
![V = \dfrac{72000}{100^3} m^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B72000%7D%7B100%5E3%7D%20m%5E3)
![V = 0.072\,m^3](https://tex.z-dn.net/?f=V%20%3D%200.072%5C%2Cm%5E3)
by simply converting the side-lengths to meters beforehand can give you this answer directly:
![V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3](https://tex.z-dn.net/?f=V%20%3D%200.3%20%5Ctimes%200.3%20%5Ctimes%200.8%20%3D%200.072%20m%5E3)
it is given that 1 meter cube of water weighs about 2200 pounds.
![1\,m^3 = 2200 \,\text{lb}](https://tex.z-dn.net/?f=1%5C%2Cm%5E3%20%3D%202200%20%5C%2C%5Ctext%7Blb%7D)
multiply both sides with 0.072 to find our answer:
![1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}](https://tex.z-dn.net/?f=1%5C%2Cm%5E3%20%5Ctimes%200.072%20%3D%202200%20%5Ctimes%200.072%20%5C%2C%5Ctext%7Blb%7D)
![0.072\,m^3 = 158.4 \,\text{lb}](https://tex.z-dn.net/?f=0.072%5C%2Cm%5E3%20%3D%20158.4%20%5C%2C%5Ctext%7Blb%7D)
hence the weight of the water in the tank would be 158.4 pounds!
Answer:
The maximum height of the arrow is 125 feet.
Step-by-step explanation:
The pathway of the arrow can be represented by the equation,
.....(1)
Where h is height in in feet and t is time in seconds.
It is required to find the maximum height of the arrow. For maximum height,
.
So,
![\dfrac{d(-16t^2 +80t + 25)}{dt}=0\\\\-32t+80=0\\\\t=\dfrac{80}{32}\\\\t=2.5\ s](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%28-16t%5E2%20%2B80t%20%2B%2025%29%7D%7Bdt%7D%3D0%5C%5C%5C%5C-32t%2B80%3D0%5C%5C%5C%5Ct%3D%5Cdfrac%7B80%7D%7B32%7D%5C%5C%5C%5Ct%3D2.5%5C%20s)
Put t = 2.5 s in equation (1). So,
![h = -16(2.5)^2 +80(2.5) + 25\\\\h=125\ \text{feet}](https://tex.z-dn.net/?f=h%20%3D%20-16%282.5%29%5E2%20%2B80%282.5%29%20%2B%2025%5C%5C%5C%5Ch%3D125%5C%20%5Ctext%7Bfeet%7D)
So, the maximum height of the arrow is 125 feet.
Answer:
3$
Step-by-step explanation: if he try to buy as many balloons as passible with the money he has it would be 3$
To evaluate this function, we use the calculator. We change the setting to radian first because we are using pi and thensimply input the cosine of 7 pi over 8. Then we square the answer. <span>We expect this number to be less than 1. </span>The function value is 0.8536.
Answer: The answer is (B). 1.01257486...
Step-by-step explanation: We are given four real numbers out of which we are to select the one which is irrational.
Option (A) is 0.12, in which the digits after the decimal are terminating. So, the number is rational.
Option (B) is 1.01257486..., the digits after the decimal are non-terminating and non-recurring. So, the number is irrational.
Option (C) is 0.1212121212..., in which the digits after the decimal are non-terminating and recurring. So, the number is rational.
Option (D) is 0.11111111..., in which the digits after the decimal are non-terminating and repeating. So, the number is rational.
Thus, (B) is the correct option.