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noname [10]
3 years ago
15

How far apart are the cities ??

Mathematics
1 answer:
Scilla [17]3 years ago
6 0
DONT go into those links they’re scams
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What is the first step in solving ln(x − 1) = ln6 − lnx for x?
Zarrin [17]
The first step to solving this problem is Multiplying In(x-1).
8 0
3 years ago
Read 2 more answers
Find the area of each shape. Show your reasoning.
Troyanec [42]

Answer:

Those areas are: A 1 = 12,  A 2 = 19

Step-by-step explanation:

The area of shape 1  : it consists of 1 square + 4 right triangles

Area of the square: A = a², area of the triangle: A = 1/2 · a · h

A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12

The area of shape 2 :  it consists of 2  isosceles triangles

A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19

3 0
3 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
Please help me with this
kaheart [24]

Answer:

m9 = 115

m4 =110

m10=65

m11= 70

m8= 70

m5 = 65

m3 = 70

m14 = 115

4 0
3 years ago
What is the area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48
Nesterboy [21]

Answer:

The area of cylinder 949.536 in²

Step-by-step explanation:

Points to remember

Curved surface area of cylinder = 2πrh

Where r - radius of cylinder

h - Height of cylinder

<u>To find the area of cylinder</u>

Here r = diameter/2 = 6.3/2 = 3.15 in

h = 48 in

Area =  2πrh

 = 2 * 3.14 * 3.15 * 48

= 949.536 in²

Therefore area of cylinder 949.536 in²

4 0
3 years ago
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