It is given that one third of restaurant is given away and the value that remains is $15000.
If one third is gone that means two thirds of the restaurant is valued at $15000.
Let the value of the restaurant be x.
So the original value of the restaurant was $22,500.
Option A is correct.
1. 3!/5! = 3*2 / 5*4*3*2 = 6/120 = 1/20
2. 5! / 8! = 5*4*3*2 / 8*7*6*5*4*3*2 = 120 / 40320 = 1/336
3. 9!/9! = 1
4. 7! / 8! = 7*6*5*4*3*2 / 8*7*6*5*4*3*2 = 5040 / 40320 = 1/8
5. 5! / 7! = 5*4*3*2 / 7*6*5*4*3*2 = 120 / 5040 = 1/42
Answer:
270/1.5=k/5
Step-by-step explanation:
270 km........1.5 h
k km........5 h
270/1.5=k/5
X=.362 or X=29/80................................