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belka [17]
3 years ago
7

Simplify the following rational expression. (HELP PLS?)

Mathematics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

Simplified expression: \frac{1}{y+8 }.

The value of y that makes the expression undefined is y=-8.

Step-by-step explanation:

\frac{2y^{3}}{2y^{4}+16y^{3}}

= \frac{2y^{3}}{2y^{3}(y+8) }

(cancel out 2y³)

=\frac{1}{y+8 }

A rational expression is undefined when the denominator (bottom number) is  zero. So, if y equalled -8, the expression would ultimately equal \frac{1}{0}, which is undefined.

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How to find equation hyperbola with asymptotes, center and transverse?
lapo4ka [179]
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate 
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola. 
6 0
3 years ago
A line, y = mx +b, passes through the point (2,3) and is parallel to y = 2x + 3. What is the value of
diamong [38]

Answer:

The value of b is 3

Step-by-step explanation:

mx is the slope and b is the y intercept. I hope this helps!

4 0
3 years ago
What is the solution?
exis [7]

Answer:

no solution

Step-by-step explanation:

The lines do not cross at any point; therefore, there is no solution.

3 0
3 years ago
I need help with three math (algebra) problems?
Bumek [7]
1.
A. (49-8)*2-16, 41*2-16, 82-16, 66, yep
B. 49-8*-14, 49+112, 161, nope
C. 7^(-16)-16, (1/(7^16))-16, nope
D. 49-16-16, 17, nope

A is answer


2.
2((a+b)²-b)
2((7+1)²-1)
2((8)²-1)
2(64-1)
2(63)
126
C is answer


4.
none of the options give the answer
3 0
3 years ago
Find the diameter(s) of circle O.
schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

BC^2=r^2+r^2=2r^2

Thus we have

2r^2=(6\sqrt{2})^2

2r^2=72

r^2=36

r=6

The diameter of the circle O is D=2(6) = 12 units

5 0
3 years ago
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