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kirza4 [7]
3 years ago
10

Chris makes $25 an hour and is getting a 10% raise. What is her new earning per hour?

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
8 0

Answer:

$27.50

Step-by-step explanation:

Hope this helps and have a great day!!!!

Elodia [21]3 years ago
4 0

Step-by-step explanation:

Since his pay is increased by 10 percent, then you multiply 10% by 25 and then add that to 25.

25+10/100(25)=55/2

27.5

Hope that helps :)

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height
Ilia_Sergeevich [38]

Answer:

\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}

From this point on, you have two possibilities, either you find each individual y_{f}, y_{0}, t_{f}, t_{0} and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

t_{f}-t_{0}=\Delta t

and we also know that:

t_{f}=t_{0}+\Delta t

in order to find the final position, we can substitute this final time into the function, so we get:

y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}

so we can rewrite our formula as:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}

y_{0} will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

y_{0}=29t-22t^{2}

y_{0}=29(1)-22(1)^{2}

y_{0}=7ft

we can substitute it into our average velocity equation:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}

and we also know that the initil time will always be 1, so we can substitute it as well.

\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}

so we can now simplify our formula by expanding the numerator:

\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}

\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}

we can now simplify this to:

\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}

Now we can factor Δt to get:

\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}

and simplify

\overline{v}=-15-22\Delta t

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s

\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s

\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s

\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s

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What is the formula for converting Celsius to Fahrenheit?
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Answer:

32 degrees fahrenheit =

0 degrees celsius

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3 years ago
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(4x^2+1)+(4x^2+x+2) what’s the sum ?
pochemuha

Answer:

(4 {x}^{2}  + 1) + (4 {x}^{2}  + x + 2) \\ 4 {x}^{2}  + 1 + 4 {x}^{2}  + x + 2 \\  = 8 {x}^{2}  + x + 3

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Jake has made a scale drawing of a sand pit he
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Answer: The scale is 5cm/m  (5 cm in the drawing are equivalent to 1 meter on the actual pit)

Step-by-step explanation:

When we have an original measure M, and we redraw it with a new scale, where the new measure is m, the scale used is equal to:

scale = m/M.

In this case, we know that:

The pit is 3m, by 5m

and the drawing to scale is 15cm by 25cm

(15cm is the rescaled version of the 3m side, and 25cm is the rescaled version of the 5m side)

Using the equation above, we can find that the scale is:

Scale = 15cm/3m = 5cm/m

and, if we use the other side, we get:

Scale = 25cm/5m = 5cm/m

Both calculations give the same scale, as expected.

Then the scale is 5cm/m, which means that 5 centimeters in the drawing are equivalent to one meter in the real pit.

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3 years ago
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