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Vaselesa [24]
2 years ago
8

The line with gradient-4 which cuts the y axis at -2​

Mathematics
1 answer:
Helen [10]2 years ago
8 0

Answer:

• Considering the general equation of a line

y = mx + b

m is the gradient and b is the y-intercept.

Substitute:

{ \underline{ \underline{ \:  \: y =  - 4x - 2 \:  \: }}}

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Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)
tigry1 [53]

Answer:

M(x,y) = (1,3) belongs to the line y = 2\cdot x +1. Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

y=k\cdot x + b

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

k - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that b = 1, x = 1 and y = 3, then we clear slope and solve the resulting expression:

k = \frac{y-b}{x}

k = \frac{3-1}{1}

k = 2

Then, we conclude that point M(x,y) = (1,3) belongs to the line y = 2\cdot x +1, whose graph is presented below.

3 0
3 years ago
(Q6) Decide if the function is an exponential function. If it is, state the initial value and the base. y= -4.8·4^x
topjm [15]

Answer:

D

Step-by-step explanation:

Exponential equation takes the form  y=a*b^x  where

  1. a is the initial value ( a ≠ 0), and
  2. b is the base ( b ≠ 1)

The equation given in the problem can be written as  y=-4.8*4^x, so it is <em>an exponential equation, </em>  where a = -4.8 and b = 4.

Thus we can say that the initial value = -4.8 and the base is 4

The correct answer is  D

3 0
3 years ago
Solve for x 49 = 2592/x
adoni [48]

ok so basically x=1/2 which is the exact form. and the decimal form is x=0.5  Step-by-step explanation:

6 0
2 years ago
Need help with #1 and #2 on this page. Thanks!
iogann1982 [59]

Find the probability of obtaining 3 heads when flipping 4 coins

7 0
3 years ago
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
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