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3 years ago

Write in base two the following numbers: one, two, four, eight, and sixteen.

Mathematics

1 answer:

Vikki [24]3 years ago

3 0

Answer:

1 is 1 in base 2

2 is 10

4 is 100

8 is 1,000

16 is 10,000

Step-by-step explanation:

Here, we want to write the numbers in base 2;

We simply divide each by 2 and note the remainders;

For 1 ; in base two , the answer is 1

for 2 in base two, the answer is 10

For 4 in base two, the answer is; 100

For 8, the answer is 1000

For 16 , the answer is 10,000

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90% of the students at Lincoln Middle School attended orientation. If 450 students attended orientation, how many students are a

pentagon [3]

Answer:

495 students are at Lincoln Middle School

Step-by-step explanation:

450/?

450 = 90%

450*90% = 450 * 0.90 = 405

450- 405 = 45

450+45 = 495

4 0

3 years ago

What is the exponent of 36

solong [7]

Since 36 = 36^1 I would say the exponent is 1

5 0

3 years ago

last year,about 2400 people particapted ina local Fourth of July parade. This year,about 3200 people participated. What was the

skad [1K]

3200-2400=800 peoples

6 0

3 years ago

Turn 12.5 into a decimal

jek_recluse [69]

12.5 is already a decimal...

If you mean 12/5, then it is 2 and 2/5, which is 2.4.

If you mean 12 x 5, then it's 60.

If you mean fractions equivalent to 12.5 then it's 25/2.

If you mean decimals then 12.50, or 12.500.

Hope this helps

5 0

4 years ago

find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho

____ [38]

For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.

8 0

4 years ago