Answer:
A.
Step-by-step explanation:
so, the equation is
h(t) = -t² + 7t
so, we need to find the solutions for t (the time when the ball is exactly 10 ft in the air). there had to be 2 solutions, as the ball first goes up passing the 10 ft height, and then comes back down again, passing the 10 ft mark a second time. and between these 2 times the ball is higher (but not equal, so, we can only use < or > as inequality signs) than 10 ft.
10 = -t² + 7t
-t² + 7t - 10 = 0
the generation solution to a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = t
a = -1
b = 7
c = -10
t = (-7 ± sqrt(7² - 4×-1×-10))/(2×-1) =
= (-7 ± sqrt(49 - 40))/-2 = (-7 ± sqrt(9))/-2
t1 = (-7 + 3)/-2 = -4/-2 = 2 seconds
t2 = (-7 - 3)/-2 = -10/-2 = 5 seconds
so, between 2 and 5 seconds airtime the ball is higher than 10 ft.
and remember : HIGHER THAN.
so, we cannot use any equality (like <= or >=).
t must be higher than 2 and lower than 5 :
2 < t < 5
We are given zeros of the polynomial : 7, -11, and 2 + 8i.
Note: The radical zero always comes with the pair of plus and minus sign.
Therefore, another zero would be 2-8i.
Now, in order to find the polynomial with the zeros 7, -11, 2 + 8i and 2-8i, we need to find the factors of the polynomial.
The factors of the polynomial would be (x-7)(x+11)(x-2-8i)(x-2+8i).
Let us multiply those factors to get the standard form of the polynomial.
=
.
<h3>Therefore, correct option is 4th option
.</h3>
Slope = (-6 - 2)/(-1 - 3)= -8/-4 = 2
answer
slope = 2
Answer:
You can have it as a decimal (0.6 repeatings), or you can have it as a fraction. It would be easier to keep it as a fraction.
A = about 295.86 if you the diameter then you know what the radiaus is. the formula is A=πr(r+h^2+r^2<span>)</span>
