Answer:The obvious difference between substitution and elimination reactions is that substitution reactions replace one substituent with another while elimination reactions simply remove the substituent. ... The major difference between the groups is the number of steps the reaction takes place over.
Step-by-step explanation:
75n-36=21n^2 rearrange so we have an equation equal to zero...
21n^2-75n+36=0 divide whole equation by 3
7n^2-25n+12=0 now factor...
7n^2-21n-4n+12=0
7n(n-3)-4(n-3)=0
(7n-4)(n-3)=0
Since this is an integer 4/7 is extraneous.
The integer value is 3
This factors to 64 - 4i^2
64 + 4
68 is the answer
