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3 years ago

PLS HELP ME AND SHOW WORK.

Mathematics

1 answer:

mario62 [17]3 years ago

3 0

Answer:

$(x-2)^{2} +(y+6)^{2} =49$

Step-by-step explanation:

equation of circle =

$(x-h) ^{2} + ( y-k)^{2} = r^{2}$

( h , k ) = center of origin

$r^{2}$ = radius

origin = ( 2 , -6 )

radius = 7

$(x-2)^2+(y+6)^2=49$

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Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

How do you work out this problem?<br><br>3x+15=66

vivado [14]

3x + 15 = 66

3x = 51

Divide 51 by 3 which equals 17.

4 0

3 years ago

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I need help if you answer this I will give you 5 stars, a thank you and a brainiest

grigory [225]

Answer:

200 / (3.14*(28/12)) = 27.3

Step-by-step explanation:

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3 years ago

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Line segment ab has endpoints a(9, 3) and b(2, 6). find the coordinates of the point that divides the line segment directed from

Dominik [7]

When we are to divide the line segment such that the ratio is 1:2, there are actually 3 parts of the segment. First, we determine the distance between the coordinates and divide the distance by 3. Then, we add the quotient to the x-coordinate.

x-coordinate: (2 - 9) / 3 = -7/3
y-coordinate: (6 - 3 ) / 3 = 1

Adding them to the coordinates of a,
x - coordinate: (9 - 7/3) = 20/3
y - coordinate: (3 + 1) = 4
Thus, the coordinates are (20/3, 4).

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3 years ago

What’s the expression of this in simplest form

Ad libitum [116K]

Answer:

3/17

Step-by-step explanation:

3/4 divided by 4 1/4 is = to 3/4 divided by 17/4= 3/4 times 4/17 = 3/17

4 0

2 years ago

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