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ollegr [7]
2 years ago
11

Question 1 of 10

Mathematics
1 answer:
Sonbull [250]2 years ago
8 0

The statement regarding the expansion of (x + y)" that is correct is D. The coefficients of yn - 1 and yn – 1 both equal 1.

<h3>How to expand?</h3>

It should be noted that for any positive integer, n, the expression of (x + y)^n will be C(n,0)x^n + C+n, 1)x^n-1 .... C(n, n)y^n.

Here, the statement regarding the expansion of (x + y)" that is correct is that the coefficients of yn - 1 and yn – 1 is both equal to 1.

Learn more about expansion on:

brainly.com/question/29114

#SPJ1

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Verify sin2θ/1+cos2θ =tanθ
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Answer:

LHS.= Sin 2x /( 1 + cos2x )

We have , sin 2x = 2 sinx•cosx

And. cos2x = 2cos^2 x - 1

i.e . 1+ cosx 2x = 2cos^2x

Putting the above results in the LHSwe get,

Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x

=sinx / cosx

= Tanx

.•. sin2x/(1 + cos2x)= tanx

Step-by-step explanation:

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Step-by-step explanation:

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Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5
Fynjy0 [20]

Answer:

a(6) = 37.97

Step-by-step explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

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Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

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