The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
Answer: -2/5
Step-by-step explanation:
To find the slope, we set the function use y = mx + b forms.
2x + 5y = 10
5y = -2x + 10 Minus 2x in both side
y = -2/5x + 10/5 Divide 5 from both side
y = -2/5x + 2
In the y = mx + b, the m before variable x is always the slope, so -2/5 is the slope for 2x + 5y = 10.
Answer:
1.5 - 1 1/5 = 3
10
= 0.3
Step-by-step explanation:
Answer:
174 1/3
Step-by-step explanation:
this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?
Answer:
Reasons:
The given parameters are;
Distance between the two stations = 146 miles
Location of the weather balloon from the Western station = N35°E
Location of the weather balloon from the Eastern station = N23°E
The location of the station = On the equator
Required:
The distance of the balloon from the Western station
Solution:
- The angle formed between the horizontal, and the line from the Western station
to the balloon = 90° - 35° = 55°
- The angle formed between the horizontal, and the line from the Eastern station
to the balloon = 90° + 23° = 113°
The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°
By sine rule,
Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)
Therefore;
Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4
Step-by-step explanation:
