Answer:
Date Account Title Debit Credit
XX-XX-XXX Sales returns and Allowances Rs. 5,000
Accounts receivable - M Center Rs. 5,000
Inventory Rs. 5,000
Cost of Goods sold Rs. 5,000
The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars
Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:
y = x - 6 (1)
The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:
xy = 112 (2)
Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.
Using the value of y from equation 1 to 2, we get:
x(x - 6) = 112 (3)
This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.
To perform the following operation, make sure to do the division parts separately and place them back together in the final answer.
10/2 and x^5/x^2
5 and using the exponential laws of division X ^m/X^n = X ^ m-n
The second part evaluates to X^3.
Putting the terms together we get the final answer, which is 5x^3.
L being the length, W being the width.
So:
if the Length is 8cm more than twice the width, we have:
2W+8
so it's:
perimeter of a rectange = 2(2W+8)+2W
You asked me not to simplify it, so that should be your answer.
Answer:
2-1=1
1+50=51
Step-by-step explanation:
