to find the inverse exchange the x and y and then solve for y
y =2x^2
x =2y^2
divide by 2
x/2 = y^2
take the square root of each side
sqrt(x/2) =y
the inverse of y =2x^2 is sqrt(x/2)
The answer appears to be choice 3 because it resembles an exponential function.
But I might be wrong.
Hope this helps :)
~ Your Cookie Monster
-5x^3 + 2x^2 + 1
a coefficient is the number that is multiplied by the variable.For instance, the coefficient of 2x is 2....because 2 (the number) is multiplied by the variable x.
so in ur problem....there are 2 coefficients..-5 and 2.
** the number 1 is not a coefficient, it is a constant...a " loner " with no variables (letters) attached.
** and if u have just the letter...such as n, the coefficient to that is 1 but the one is just not written...it is actually 1n.
okay...I am gonna shut up now :)
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
1. x=5/2
2. x=3/4-3/4y
y belongs R
