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3 years ago

10

For which intervals the graphs of the functions f(x) = x^3 + x^2 - 4x - 4 is positive

1 answer:

Nookie1986 [14]3 years ago

5 0

Step-by-step explanation:

Consider a function

f

(

x

)

which is twice differentiable. The graph of such a function will be concave upwards in the intervals where the second derivative is positive and the graph will be concave downwards in the intervals where the second derivative is negative. To find these intervals we need to find the inflection points i.e. the x-values where the second derivative is 0.

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Combine the like terms to create an equivalent expression.<br> 4n+6+n-2

NemiM [27]

5n+4 seems to be the answer

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3 years ago

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Find the angle measurements and side lengths for the triangle below

rewona [7]

Answer:

Step-by-step explanation:

Sin(A) = 5/7

Sin(A) = 0.7143

A = sin-1(0.7143

A = 45.58

B = 180 - 45.58 - 90

B = 44.43

C = 90

c = 7

a = 5

b^2 = c^2 - a^2

b^2 = 7^2 - 5^2

b^2 = 49 - 25

b^2 = 24

b = 4.899

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2 years ago

What number is represented by 8^-3

blsea [12.9K]

Fraction: 1/512
decimal: 0.001953

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3 years ago

What is the value of sec theta given the diagram below?

marishachu [46]

Answer:

$\sec \theta=-\sqrt{5}$

Step-by-step explanation:

The hypotenuse is $h^2=6^2+3^2$

$h^2=36+9$

$h^2=45$

$h=\sqrt{45}$

$h=3\sqrt{5}$

The terminal side of $\theta$ is in the second quadrant.

In this quadrant; the secant ratio is negative.

$\sec \theta=-\frac{hypotenuse}{adjacent}$

$\sec \theta=-\frac{3\sqrt{5}}{3}$

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6 0

3 years ago

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Find the percent change from the first value to the second.<br><br> 50; 39

sertanlavr [38]

Answer:

11 percent

Step-by-step explanation:

if you subtract 50 - 39 = 11

so 11 percent is the change from the first value to the second value.

Hope this helps :)

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3 years ago