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PtichkaEL [24]
3 years ago
14

A square garden with side length of 50 has a square shaped fountain display with length of 12 feet at the exact center of garden

find the area of the garden
Mathematics
1 answer:
nadezda [96]3 years ago
6 0

Answer:

The area of the garden is 2356\ ft^2

Step-by-step explanation:

<u>Area of a Square</u>

Given a square of a side length of x, the area is calculated as:

A = x^2

There is a square garden area of a side length of x=50 feet. The area is:

A_1=50^2=2500\ ft^2

Inside of it, there is another square area for a fountain display of a side length of 12 feet. The area is:

A_2=12^2=144\ ft^2

The area of the garden is the difference between A2 and A1:

A_g=A_2-A_1=2500\ ft^2-144\ ft^2

A_g=2356\ ft^2

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Please help
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Answer:

(-6,4)

Step-by-step explanation:

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Now we can solve for y:

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A quadratic rule for a particular parabola is of the form y = ax^2 + bx. The parabola passes through with the coordinates (-1, 4
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6 0
3 years ago
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