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PtichkaEL [24]
3 years ago
14

A square garden with side length of 50 has a square shaped fountain display with length of 12 feet at the exact center of garden

find the area of the garden
Mathematics
1 answer:
nadezda [96]3 years ago
6 0

Answer:

The area of the garden is 2356\ ft^2

Step-by-step explanation:

<u>Area of a Square</u>

Given a square of a side length of x, the area is calculated as:

A = x^2

There is a square garden area of a side length of x=50 feet. The area is:

A_1=50^2=2500\ ft^2

Inside of it, there is another square area for a fountain display of a side length of 12 feet. The area is:

A_2=12^2=144\ ft^2

The area of the garden is the difference between A2 and A1:

A_g=A_2-A_1=2500\ ft^2-144\ ft^2

A_g=2356\ ft^2

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Answer:

1) h=\frac{8\sqrt{3}}{3}\ units

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Step-by-step explanation:

Part 1) Find the height of the pyramid

we know that

tan(30^o)=\frac{h}{(b/2)}

where

h is the height of the pyramid

b is the length side of the square base

we have

tan(30^o)=\frac{\sqrt{3}}{3}

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substitute

\frac{\sqrt{3}}{3}=\frac{h}{(16/2)}

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Part 2) Find the volume of the pyramid

we know that

The volume of the pyramid is equal to

V=\frac{1}{3} Bh

where

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h is the height of the pyramid

we have

B=(16^2)=256\ units^2

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substitute

V=\frac{1}{3} (256)(\frac{8\sqrt{3}}{3})

V=\frac{2,048\sqrt{3}}{9}\ units^3

8 0
3 years ago
27. Find the length of the segment LK. (G.CO.C.10)
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so, both sides of the baseline must be equal :

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x = 3

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