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STALIN [3.7K]
3 years ago
6

What is the value of the expression 10 (n minus 6) when n = 14?

Mathematics
2 answers:
Scrat [10]3 years ago
6 0

Answer:

The value of the expression is 80.

Step-by-step explanation:

14 - 6 = 8.

10 x 8 = 80.

earnstyle [38]3 years ago
5 0

Answer: 80

Step-by-step explanation:

Your original equation is 10(n - 6)

You know what the value of n is: 14

Now go into your equation since the value of n is 14, replace n with 14 giving you the expression

10(14 - 6)

Now do the subtraction inside the parentheses

10(8) = 80

That should be your answer I hope this helps you :)

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Need help adding these<br><br> √54 + √24
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Answer:

12.247 Hope I helped

Step-by-step explanation:

\sqrt{54}+\sqrt{24}  \\7.348+4.899\\12.247

8 0
3 years ago
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What is 6 over 9 simplified
Snezhnost [94]

Answer:

2/3

Step-by-step explanation:

\frac{6}{9}

\frac{6}{9}  =  \frac{2 \times 3}{3 \times 3}

=  \frac{2}{3}  \times  \frac{3}{3}

=  \frac{2}{3}  \times 1 =  \frac{2}{3}

I hope it helped you

3 0
2 years ago
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A line has a y-intercept of 4 and a slope of 2/3. Explain how you can use this
Dafna1 [17]

Answer:

0,2 0r 2/2

Step-by-step explanation:

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Ava poured 3 gallons of paint equally into 5 cans. How many gallons of paint will there be in each can
FromTheMoon [43]

Answer:

0.6 gallons/can

Step-by-step explanation:

Simply divide the gallons of paint by the number of cans:

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The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
1 year ago
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