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olasank [31]
3 years ago
5

12x-4<16 Please helpppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

x < 1.66666666667

Step-by-step explanation:

Step 1:

12x - 4 < 16           Equation

Step 2:

12x < 20           Add 4 on both sides

Step 3:

x < 20 ÷ 12        Divide

Answer:

x < 1.66666666667

Hope This Helps :)

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trapecia [35]
I would say two is the right one
4 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
What angle is this and explain
REY [17]

The measures of the angles are 59 degrees

<h3>How to determine the value of the angles?</h3>

The angles are given as:

Angle 1 = 2x + 17

Angle 2 = 3x - 4

By the interior angle theorem, the angles are congruent

So, we have

Angle 1 = Angle 2

Substitute the known values in the above equation

2x + 17= 3x - 4

Collect the like terms

3x - 2x = 17 + 4

Evaluate the like terms

x = 21

Substitute x = 21 in Angle 1 = 2x + 17

Angle 1 = 2 * 21 + 17

Evaluate

Angle 1 = 59

This means that

Angle 1 = Angle 2 = 59

Hence, the measures of the angles are 59 degrees

Read more about angles at:

brainly.com/question/25716982

#SPJ1

8 0
1 year ago
Bernard solved the equation 5x+(-4)=6x+4 using algebra tiles.Which explains why Bernard added 5 negative x-tiles to both sides i
Volgvan
5x+(-4)-5x=6x+4-5x
-4=x+4
x=-8

To get rid of 5x on the left side.
6 0
3 years ago
Read 2 more answers
Which expressions are equivalent to -6+49 + (-69)?
m_a_m_a [10]

Answer:

I'm pretty sure it's none of the above

Step-by-step explanation:

Sorry if you get it wrong :/

3 0
3 years ago
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