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8090 [49]
3 years ago
7

Bernard solved the equation 5x+(-4)=6x+4 using algebra tiles.Which explains why Bernard added 5 negative x-tiles to both sides i

n the first step of the solution ?
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

To remove 5x and create and linear equation

Step-by-step explanation:

5x+(-4)=6x+4

The equation can be solved by arranging terms so that numbers can be on one side and other constants will be on the other side.

This is given by the associative rule that states:

(-5x) + 5x + (-4) = 6x +4 - 5x

giving:

-4 = x + 4

this gives, x= -8

Hence a linear equation with a solution.

Volgvan3 years ago
6 0
5x+(-4)-5x=6x+4-5x
-4=x+4
x=-8

To get rid of 5x on the left side.
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Y = 4x
(-2,y).....x = -2

y = 4(-2)
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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
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\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
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ILL MARK BRAINLIEST
SpyIntel [72]
Y=3x-5

Y=5/4x+3/4

The solution to the equations is in the picture

7 0
3 years ago
1/4(1-2/3)^2+1/3 Simplify
MrMuchimi

Simplifying the expression gives 13/ 36

<h3>How to solve the expression</h3>

Given;

1/4(1-2/3)^2+1/3

Represented as;

\frac{1}{4} * ( 1  - \frac{2}3} )^2 + \frac{1}{3}

Take the LCM of the bracket

\frac{1}{4} * ( \frac{1}{3} )^2 + \frac{1}{3}

Find the square

\frac{1}{4} (\frac{1}{9} )+ \frac{1}{3}

Find the LCM

\frac{1}{36} + \frac{1}{3}

1 + 12/36

13/ 36

Thus, simplifying the expression gives 13/ 36

Learn more about fractions here:

brainly.com/question/1622425

#SPJ1

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1 year ago
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