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Nataly [62]
2 years ago
10

Which expression is equivalent to 2(3g - 4) - (8g + 3)?

Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0

Answer:

Step-by-step explanation:

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Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p
ludmilkaskok [199]

Answer:

a. Quotient property of logarithms, P = log[(d + 1)/d]

b.  log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

8 0
2 years ago
Round your answer to the nearest hundredth.
Serga [27]

Answer:

cos(a) =  \frac{ac}{ab}  \\ cos \: 40° =  \frac{x}{4}  \\ x = 4 \cos40° \\ x = 3.0641 \\  \\ approimatly \\ x = 3.06

4 0
1 year ago
A ball is kicked off of the roof of a building. The path the ball travels is modeled by the equation f(x)= -x^2 + 6x+ 16, where
damaskus [11]

Answer:

This question is a rather easy one which can be answered by simply solving the embedded quadratic equation.

f(x) = -x^{2} + 6x + 16

To make our solving easier, what we do is multiply the whole equation by -1. By so doing, we make "x" positive. Then, we have

f(x) = x^{2} - 6x - 16

Solving this equation quadratically, we have

x^{2} + 2x - 8x - 16 = and when we factorize this expression, we have

x(x + 2) -8(x + 2) =

(x - 8) (x + 2) = 0

x - 8 = 0, x + 2 = 0

x = 8, or  x = -2

Since distance can not be in negative(minus), we then have our x to be 8 meters.

Another example on factorization can be seen here  brainly.com/question/13813750

3 0
2 years ago
What is the Ratio of 472 and 482?
Lemur [1.5K]
The answer to your question is

answer: 236/241

❤️❤️!!
8 0
2 years ago
Read 2 more answers
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
2 years ago
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