The SQL statement that would create the GET_CREDIT_LIMIT procedure to obtain the full name and credit limit of the customer is:
GET_CREDIT_LIMIT
SELECT CUST_ID 125
FROM FIRST_NAME, LAST_NAME, CREDIT_LIMIT
WHERE LAST_NAME ="Smith"
<h3>What is SQL?</h3>
This is an acronym that means Structured Query Language that is used in handling data in a database.
Hence, we can see that from the attached image, there is a table that contains the details of customers and their various data such as their first and last names, credit limits, address, etc, and the GET_CREDIT_LIMIT procedure is shown above.
Read more about SQL here:
brainly.com/question/25694408
#SPJ1
Answer:

Explanation:
We'll be using u-substitution for this problem.
Let

Substitute

Split the fraction

Move the constants out

Simplify

Integrate

Substitute

Answer: A.)true
Explanation: This is true for a number of reasons, the first being that synced files
Using the python code we can say that it will be possible to calculate the neutrons and organize them as:
<h3>The code can be written as:</h3>
<em>def get_total_derivative(self,l_id):</em>
<em>def sigmoid(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.exp(-x) / (1. + np.exp(-x))**2.</em>
<em>if div == 2: </em>
<em>return - np.exp(x) * (np.exp(x) - 1) / (1. + np.exp(x))**3.</em>
<em>return 1. / (1. + np.exp(-x)) </em>
<em />
<em>def linear(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.full(x.shape,1)</em>
<em>if div > 2: </em>
<em>return np.zeros(x.shape)</em>
<em>return x </em>
<em />
<em />
<em />
See more about python at brainly.com/question/18502436
#SPJ1
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).