In this activity Morgan is preparing the digital files to a printer on a DTP project.
Explanation:
DTP project is the creation of documents using page layout on a personal computer. The process of printing digital based images directly to variety of media substrates is known as digital processing.
The digital files like PDFs can be sent directly to digital printing press to print on paper, photo paper, fabric and so on.
They have unique fade rates and different sensitives to the various deterioration mechanisms. DTP is used for graphic designers to create documents.
Ben should set up a program to teach his staff about customer service, and communicating with clients.
The pseudocode to calculate the average of the test scores until the user enters a negative input serves as a prototype of the actual program
<h3>The errors in the pseudocode</h3>
The errors in the pseudocode include:
- Inclusion of unusable segments
- Incorrect variables
- Incorrect loops
<h3>The correct pseudocode</h3>
The correct pseudocode where all errors are corrected and the unusable segments are removed is as follows:
start
Declarations
num test1
num test2
num test3
num average
output "Enter score for test 1 or a negative number to quit"
input test1
while test1 >= 0
output "Enter score for test 2"
input test2
output "Enter score for test 3"
input test3
average = (test1 + test2 + test3) / 3
output "Average is ", average
output "Enter score for test 1 or a negative number to quit"
input test1
endwhile
output "End of program"
stop
Read more about pseudocodes at:
brainly.com/question/11623795
Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
