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3 years ago

Can you help me I forgot

Mathematics

2 answers:

Rzqust [24]3 years ago

4 0

Harrison walked a total of 14 km because the first rectangle has a perimeter of 6 km and the second has a perimeter of 8 km. Harrison’s brother walked a total of 12 km since that was the perimeter of the 5*1. 14-12 is 2 so there is a 2 km difference.

gregori [183]3 years ago

4 0

He walked 14 km and there was a 2 km difference

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In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies. They describe ad agency outp

fredd [130]

Answer: (7.27%, 7.55%)

Step-by-step explanation:

As per given , we have

Sample size : n= 392

Sample mean : $\overline{x}=7.41\%$

$\sigma=1.43\%$

Critical two-tailed z-value for 95% confidence = $z_{\alpha/2}=1.96$

Required confidence interval would be :

$7.41\%\pm (1.96)\dfrac{1.43\%}{\sqrt{392}}\\\\=7.41\%\pm 0.14\%\\\\=(7.27\%, 7.55\%)$

Hence, the required 95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies : (7.27%, 7.55%)

7 0

4 years ago

Jason has 60 cars. 30% is blue. How many are blue?

Dmitriy789 [7]

So to figure out 10% of this would be to remove the 0. that would be six. since 30÷10 is 3, we have to do 6×3. that would be 18, so 30% of 60 is 18

5 0

3 years ago

Read 2 more answers

For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

3 years ago

Is 22+ 32 = 42 a true statement? Explain.

ivolga24 [154]

No, this is not true, 22+32 =54 this is not a true statement

4 0

4 years ago

What’s the definition To reduce a fraction or expression to its lowest term

elena-14-01-66 [18.8K]

Divide the top and bottom by the highest number that can divide into BOTH numbers.

5 0

3 years ago