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Sergeeva-Olga [200]
4 years ago
14

Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)

Mathematics
1 answer:
damaskus [11]4 years ago
5 0

The product is equal to zero if one of the factors is equal to zero.

Therefore:

y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}

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Answer:

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but \frac{1}{6} \times 6  \neq -1

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