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Sergeeva-Olga [200]
3 years ago
14

Identify the zeros for the function and sketch a graph. y=x(x-2)(x+3)

Mathematics
1 answer:
damaskus [11]3 years ago
5 0

The product is equal to zero if one of the factors is equal to zero.

Therefore:

y=x(x-2)(x+3)\\\\x(x-2)(x+3)=0\iff x=0\ \vee\ x-2=0\ \vee\ x+3=0\\\\\boxed{x=0\ \vee\ x=2\ \vee\ x=-3}

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Answer:

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Step-by-step explanation:

5 0
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7 0
3 years ago
What is the answer for 9-0-5-(-20)+(-13)?
Nitella [24]

The correct answer is: 11

Here’s how you solve it!

You can remove the 0 since when you add or subtract 0 it stays the same.

Then you would want to look at the first set of parentheses (-20)

Since it is -(-20) this changes the sign to a positive +20

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Now since the + is in front of the (-13) it remains the same.

Now you are left with this:

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