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sladkih [1.3K]
1 year ago
15

How many terms are in the binomial expansion of (2x 3)5? 4 5 6 7

Mathematics
1 answer:
padilas [110]1 year ago
8 0

In the binomial expansion (2x + 3)^5 , there are 6 terms.

According to the question, given that

Binomial expansion  (2x + 3)^5

Number of terms in a binomial expansion of (x + y)^n is

N = n + 1 words in total

In the binomial expansion (2x + 3)^5

n = 5

N = 5 + 1 = 6

Therefore, In Binomial expansion  (2x + 3)^5 there are 6 terms.

The algebraic expression (x + y)n can be expanded according to the binomial theorem, which represents it as a sum of terms using separate exponents of the variables x and y. Each word in a binomial expansion has a coefficient, which is a numerical value.

The formula for expanding the exponential power of a binomial expression is provided by the binomial theorem, sometimes referred to as the binomial expansion. The following is the binomial expansion of (x + y)n using the binomial theorem:

(x+y)^n = n_C_{0} * n_y_{0} + n_C_{1}  * n-1_y_{1} + n_C_{2} * n-2_ y_{2} + ... + n_C_{n-1} * 1_y_{n-1} + n_C_{n} * 0_y_{n}

To learn more about binomial theorem visit here : brainly.com/question/2165968

#SPJ4

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Step-by-step explanation:

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Answer:

1) 1/10

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Step-by-step explanation:

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1 favorable outcome and 10 total outcomes.

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3 years ago
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How many odd integers are there between 101 and 999 have distinct digits?
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So there are 7\cdot8\cdot8=320 such numbers.
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