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2 years ago

8

Helpppppp poooorrrfavooor plsssssss

2 answers:

Trava [24]2 years ago

8 0

Answer:

2/12

Step-by-step explanation:

nikklg [1K]2 years ago

6 0

Answer:

o

Step-by-step explanation:

o

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Plz answer i'll give brainliest but it has to be right.

Alex17521 [72]

3 -3/4 and 2 pls brainlest

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2 years ago

If p represents the original price, which of the following expressions could be used to calculate the sale price of a shirt that

dezoksy [38]

Answer:

C & D

Step-by-step explanation:

You can do these two ways. You can multiply the cost of the the shirt by 15% (.15 as a decimal.) and then subtract that answer from the original price of the shirt to get the sales price of the shirt.

You can also multiply the price of the shirt by 85% (.85 as a decimal) and that will give you the sales price without having to subtract. 15% + 85% = 100%, so 85% represents the sales price of the shirt.

Anyway, since you multiply, you can eliminate choice A & B.

Since the direction in the question says to select all that apply, I would check both C & D.

C is the equation of the first way I talked about- Price - 15% * price

C p - 0.15p

D is the equation of the second way I talked about. Price times 85%

D 0.85p

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3 years ago

Solve for x. Show your work.<br><br> 34x-5 = (1/27) 2x+10

Ilia_Sergeevich [38]

Answer:The answer in a fraction is 405/916 and the decimal form is 0.44213973

…

Step-by-step explanation:

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2 years ago

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A plane cuts a pyramid as shown in the diagram. What is the shape of the cross section?

forsale [732]

The answer is a hexagon
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3 years ago

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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago