I would say A. I'm assuming this is to do with the equation y=kx, therefore A has the k value of -12
Average = mean = sum of the values / number of data
Values = h, j, and k
Number of data = 3
Sum of the values = h + j + k
Mean = [h + j + k] / 3
=> Answer: option c. [h+j+k] over 3