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WITCHER [35]
2 years ago
10

What is the square root of 8 rounded to the nearest tenth?

Mathematics
1 answer:
frozen [14]2 years ago
8 0

Square Root of 8 to the nearest tenth, means to calculate the square root of 8 where the answer should only have one number after the decimal point.

Here are step-by-step instructions for how to get the square root of 8 to the nearest tenth:

Step 1: Calculate

We calculate the square root of 8 to be:

√8 = 2.82842712474619

Step 2: Reduce

Reduce the tail of the answer above to two numbers after the decimal point:

2.82

Step 3: Round

Round 2.82 so you only have one digit after the decimal point to get the answer:

2.8

To check that the answer is correct, use your calculator to confirm that 2.82 is about 8.

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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
Round each number to the nearest 10 and 100. 734,102,483
11111nata11111 [884]
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483: 480 and 500.

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8 0
2 years ago
A covered water tank is in the shape of a cylinder the tank has 28 inch diameter and the high is 66 inches to the nearest square
posledela
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Find the missing number for 1/3 = 3:
RSB [31]
1/3=3:9
since 1×3=3
3×3=9
7 0
3 years ago
What is the value of Z?
sukhopar [10]

Answer:

Step-by-step explanation:

Both x and y are inscribed angles.  The value of an inscribed angle is half the measure of its intercepted arc.  This means that x has a value of 33°, and y has a value of 48°.  That means that, according to the triangle angle sum theorem, the third angle has to equal 180 - 33 - 48 = 99°.

This angle is vertical with angle z, so angle z also equals 99°

5 0
3 years ago
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