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3 years ago

Sixth sevenths times seven tenths

Mathematics

2 answers:

Kamila [148]3 years ago

6 0

Answer : 0.6

hope this helps !! ^-^

mestny [16]3 years ago

4 0

Answer: 0.6

Step-by-step explanation:

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Got my question for you

marta [7]

Answer:

0.999

Step-by-step explanation:

Since there are 729 possible combinations, the probablity of not getting it right is 728/729 which is 0.99862825 … and if you round that, it would be 0.999.

3 0

3 years ago

Determine whether each of these sets is countable oruncountable. For those that are countably infinite, exhibit

mezya [45]

Answer:

Answers are given below.

Step-by-step explanation:

a) one-to-one correspondence between the set of positiveintegers and that set.

Whenever we have one to one correspondence with positive integers, the set is countable and here infinite.

b) integers divisible by 5 and not 7 ..This set is all integers divisible by 5 but not by 7. This is a discrete set and hence countable and infinite.

c) the real numbers with decimal representationsconsisting of all 1’s

-- This cannot be counted and hence uncountable but infinite.

d) the real numbers with decimal representationsconsisting of all 1’s or 9’s

-- This is also uncountable but infinite.

6 0

3 years ago

3. Which property of multiplication is shown 1. X = X (a) associative (b) commutative (c) distributive (d) identity

Agata [3.3K]

Answer:

X = X is <u>Commutative Property of Multiplication</u>.

4 0

3 years ago

The arithmetic sequence a_ia i a, start subscript, i, end subscript is defined by the formula: a_1 = 15a 1 =15a, start subsc

daser333 [38]

Answer:

-1,512,390

Step-by-step explanation:

Given

a1 = 15

$a_i = a_{i-1} -7$

Let us generate the first three terms of the sequence

$a_2 = a_{2-1}-7\\a_2 = a_1 - 7\\a_2 = 15-7\\a_2 = 8$

For $a_3$

$a_3 = a_{3-1}-7\\a_3 = a_2 - 7\\a_3 = 8-7\\a_3 = 1$

Hence the first three terms ae 15, 8, 1...

This sequence forms an arithmetic progression with;

first term a = 15

common difference d = 8 - 15 = - -8 = -7

n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)

Using the formula;

$S_n = \frac{n}{2}[2a + (n-1)d]\\$

Substitute the given values;

$S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390$

Hence the sum of the first 660 terms of the sequence is -1,512,390

6 0

3 years ago

Please help !!!!!!!!!!!!

zhannawk [14.2K]

Answer:

25+40

Step-by-step explanation:

for the area of a triangle you multiple the base times the height. for the area of the square it is the length times width.

NOTE: to completely answer just add 25+40

6 0

3 years ago