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slega [8]
3 years ago
7

Can you solve what is 5 x 1 2/3

Mathematics
2 answers:
polet [3.4K]3 years ago
8 0

Answer:

8.33333333

Step-by-step explanation:

enot [183]3 years ago
7 0
I believe the answer is 20 sorry
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Olve for x. -3x = -15 x = -45 x = 5 x = -5
elena-14-01-66 [18.8K]
You answer will be X=0 hope this helps
6 0
3 years ago
Which graph below shows a line that contains ordered pairs that are solutions of the equation shown?
Vinvika [58]

Given:

The equation is:

y=-x+4

To find:

The graph of the line that contains ordered pairs that are solutions of the given equation.

Solution:

We need to find the graph of the given equation.

We have,

y=-x+4

At x=0, we get

y=-0+4

y=4

So, the x-intercept of the given equation is at point (0,4).

At y=0, we get

0=-x+4

x=4

So, the y-intercept of the given equation is at point (4,0).

From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).

Therefore, the correct option is C.

7 0
3 years ago
Look at the figures. How can you prove the triangles are congruent?
ExtremeBDS [4]

Answer:

ABC = DEF by the SAS Postulate

5 0
3 years ago
What is 19.2× 10^8 minutes in hours?
algol [13]
The awnser is 1920,000,000 I hope I helped you the decimal skips eight spaces
6 0
3 years ago
Use spherical coordinates to find the limit. [Hint: Let x = rho sin(ϕ) cos(θ), y = rho sin(ϕ) sin(θ), and z = rho cos(ϕ), and no
shutvik [7]

Answer:

lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0

Step-by-step explanation:

First, we need to put the spherical coordinates equations that we will use in our problem  

x = p*sin∅cos Ф

y = p*sin∅sinФ

z=p*cos∅

Then we will state the problem  

lim (x, y, z) → (0, 0, 0)  [x*y*z]/(x^2+y^2+z^2)

Using the spherical coordinates we get  

(x^2+y^2+z^2) = p^2  

Which will make our limit be  

lim p→0+ [p*sin∅cos Ф*p*sin∅sinФ *p*cos∅]/(x^2+y^2+z^2)

after solving limit:

lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0

4 0
3 years ago
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