All categories

3 years ago

Help pls 15.5 x 5.3 x 6=

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

492.9

I have to make this 20 characters long ..

You might be interested in

Describe the transformation from the parent function to the function g(x)=2 times 3^x-4

azamat

Answer:

Step-by-step explanation:

The parent function of g(x) = 2*3^x-4 would be 3^x

The transformation would include: shifting parent function 4 units down (-4) and compressing the function (2)

The movement (shifting) of the graph is caused by the y-intercept. If the y-intercept is positive, the graph moves up and vice versa.

The coefficient which is multiplied determines whether the function is compressed (squeezed) or stretched. If the coefficient is less than 1, then the function is stretched. If the coefficient is greater than 1, then the function is compressed.

6 0

3 years ago

I need a lot of help with this plz someone help!

Vitek1552 [10]

Answer:

36.50

Step-by-step explanation:

just add them all up

8 0

3 years ago

Read 2 more answers

If 3/10 was spent warming up and cooling down how many minutes was it

777dan777 [17]

18 minutes
3/10=18/60
60 represents the hour
18 represents time spent warming up and cooling down.

4 0

3 years ago

What is a paragraph proof

pashok25 [27]

A paragraph proof<span> is only a two-column </span>proof<span> written in sentences. </span>

8 0

3 years ago

Read 2 more answers

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago