Option A: 
Option C: 
Option F: 
Solution:
Given expression is 
.
Option A:
Hence is equivalent expression of .
Option B: 
Hence is not equivalent expression of .
Option C:
(proved in option A)
Hence is equivalent expression of .
Option D: 
Hence is not equivalent expression of .
Option E: 75
75 is a whole number.
Hence 75 is not equivalent expression of .
Option F:
(proved in option A)
Hence is equivalent expression of .
Therefore, 
are all equivalent expressions of .
We are given x so we can plug it in to the first equation to find y
11 - y = 6
We don’t want y to be negative so we subtract y from both sides
11 = 6 + y
Now we can subtract 6 from both sides
5 = y
Answer:
15 cookies come in the box.
Step-by-step explanation:
20% = 1/5
3 x 5 = 15
Answer:
29.42 units
Step-by-step explanation:
<u>1) Find the perimeter around the semi-circle</u>
To do this, we find the circumference of the circle using the given diameter:
where d is the diameter
Plug in 6 as the diameter
Divide the circumference by 2
Therefore, the perimeter around the semi-circle is 3π units.
<u>2) Find the perimeter around the rest of the shape</u>
Although it's impossible to determine the lengths of the varied sides on the right side of the shape, we know that all of those <em>vertical</em> sides facing the right add up to 6. We also know that all of those <em>horizontal </em>sides facing up add up to 7. Please refer to the attached images.
Therefore, we add the following:
7+6+7
= 20
Therefore, the perimeter around that area of the shape is 20 units.
<u>3) Add the perimeter around the semi-circle and the perimeter around the rest of the shape</u>
Therefore, the perimeter of the shape is approximately 29.42 units.
I hope this helps!
Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>
Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1
∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2
∴ y = 0.12
