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3 years ago

What is the length of missing side b in the figure below?

Mathematics

2 answers:

aalyn [17]3 years ago

7 0

If you use the Pythagorean theorem you get 10.95cm, which is also the square root of 120.

Anna11 [10]3 years ago

4 0

According to the theory
b^2 = (13)^2 - (7)^2
b^2 = 169 - 49 = 120
b= root(120)
b= 10.95 cm

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What is the quadratic function that is created with roots at 2 and 4 and a vertex at (3, 1)?

Arada [10]

Hello,

y=k*(x-2)(x-4)
and is passing throught (3,1)
==>1=k*(3-2)(3-4)==>k=-1

y=-(x-2)(x-4) is an answer

4 0

3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago

5x=4y+8 3y=3x-3 using elimination

suter [353]

Let's rewrite the equation with x and y on the left side of the equal sign.
5x-4y=8 --------(1)
3x-3y=3---------(2)
Divide equation (2) by 3,
x - y= 1
now we have,
5x-4y = 8 --------(1)
x - y = 1 ---------(2)
To eliminate x, multiply equation (2) by 5. This makes both the coefficients of x to be 5. Subtract the second equation from the first equation.
5x - 4y = 8
(2) * 5 5x - 5y = 5
(-) (+) (-)
----------------
0x +y =3
Therefore, y=3
Substitute the value of y, in any one of the two equations. Let's substitute y in the second equation.
x-3=1
x=4
x=4 and y=3

8 0

4 years ago

Solve for n 36=13n-4n

Lana71 [14]

Answer:

n = 4

Step-by-step explanation:

36 = 13n - 4n

<=> 36 = (13-4).n

<=> 36 = 9n

<=> n = 36 / 9

<=> n = 4

8 0

4 years ago

Read 2 more answers

2y-2=3/2y. 10x-4=5x

GREYUIT [131]

2y-1.5y=2
0.5y=2
y=1
10x-5x=4
x=4/5

8 0

4 years ago