All categories

3 years ago

Bennett saves 12% of his income. Write the percent as a fraction and as a decimal.

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

Answer:

(fraction=12/100 or 6/50 or 3/25) (decimal form=0.12)

Step-by-step explanation:

for the decimal form percent means per hundred, so just divide the percent by 100 to get the decimal.

hope this helps!

You might be interested in

Divide 3m 80cm of ribbon in the ratio of 1/3 : 3/4 : 1/2 what is the result?

JulijaS [17]

Answer:

80 cm / 180 cm / 120 cm

Step-by-step explanation:

the smallest common multiple of 3, 4 and 2 is 12.

so, to be able to truly compare these fractions we need to bring all denominators to .../12.

1/3 = 4/12

3/4 = 9/12

1/2 = 6/12

in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :

4 parts for the first segment.

9 parts for the second segment

6 parts for the third segment.

so, one part is

380 cm / 19 = 20 cm

therefore the first segment of the ribbon is

4×20 = 80 cm long

the second segment

9×20 = 180 cm long

the third segment

6×20 = 120 cm long

4 0

3 years ago

Choose a counterexample that proves that the conjecture below is false.. abc is a right triangle, so angle A measures 90 degrees

andre [41]

Choose a counterexample that proves that the conjecture below is false.. abc is a right triangle, so angle A measures 90 degrees.

Answer: Out of all the options shown above the one that represents the counterexample that proves that the conjecture presented above is false is answer choice 2. Angle b is 90 degrees. The reason being that in a right angle there is only one angle that measures 90 degrees.

I hope it helps, Regards.

6 0

4 years ago

Read 2 more answers

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$