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telo118 [61]
3 years ago
7

the population of the US was 282 million in the year 2000. and 309 million in the year 2010. assuming that the US population fol

lows the model of uninhibited population growth, what will the population be in the year 2050?
Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

417 million

Step-by-step explanation:

309 minus 282 equals 27. That's how many people moved in 10 years.

Multiply 27 by 4 to get 108. That's how many people will move in 40 years.

Add that to 309 (the amount of people that were living in the U.S. in 2010) to get 417.

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What is 2+6 100 points the answer is 8 right?
Elan Coil [88]

Answer:

yes it is 8

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
Read 2 more answers
Mary baked 30 cookies. Her family ate of them. Using D write an expression for the number of cookies that remained
Dahasolnce [82]

Answer:

30 divided by 2 = D

Step-by-step explanation:

None

8 0
3 years ago
How many solutions does this system have? y=3/4x-5 -3x+4y=-20?
lisov135 [29]

Answer:

infinite

Step-by-step explanation:

If you multiply all factors in the secon eqation by 4, you will get the first eqation.

Therefore for any value of x you can find y, thus having an infinite number of x,y pairs

8 0
3 years ago
Sean took 4 hours to travel from Town A to Town B at an
labwork [276]

Answer:

Tina's average speed  for the whole journey = 56 kmph

Step-by-step explanation:

Time taken by Sean to travel from Town A to Town B = 4 hours.

Average speed of Sean = 70 km/h

We have equation of motion, s = ut + 0.5 at²

Time, t = 4 hours.

Initial speed, u = 70 km/hr

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x  4²

       s = 280 km

Distance from Town A to Town B = 280 km

Tina took 1 hour more than Sean.

Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours

We have equation of motion, s = ut + 0.5 at²

Time, t = 5 hours.

Displacement, s = 280 km

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      280 = u x 5 + 0.5 x 0 x  5²

       u = 56 km/hr

Tina's average speed  for the whole journey = 56 kmph

6 0
3 years ago
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