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3 years ago

8

In June, Jim ran a mile in 7 minutes and 45 seconds. After training the entire summer he ran a mile in 5 minutes and 51 seconds

in September. Find the percent of change from June to September of Jim's mile time. (Be sure to change the minutes to seconds.)

1 answer:

gregori [183]3 years ago

8 0

Step-by-step explanation:

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Can you help me with this question? 15 points and brainliest if right!!

WINSTONCH [101]

Hi um I think you posted a picture of something else other than the question!!

8 0

3 years ago

Read 2 more answers

Answer to number 6 please

Alenkasestr [34]

Answer:

Step-by-step explanation:

C

6 0

2 years ago

Kyle held a balloon 8ft off the ground above his head and Ava is standing 15 feet directly to g the right of Kyle how far is Ava

ryzh [129]

Answer:

17

Step-by-step explanation:

Pythagorean theory baby! Okay so the Pythagorean theory is a² + b² = c² so lets draw a triangle and label our sides. So we know 8² + 15² = c² so I'm going to find the square root of all of our numbers. We get 64 + 225 = c² so then add 64 + 225 = 289 then I take the square root of 289 which equals 17 . This answer also makes sense because out hypotenuse should always be bigger then the legs.

I'm pretty sure thats right, Hope this helps.

5 0

3 years ago

Find the quadratic function that fits the following data. which one function fits.

Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c$

We get the system of three equations:

$\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.$

Subtract these equations:

$\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.$

From the first equation

$b=-120a$

Substitute it into the second equation:

$5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5$

So,

$2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25$

The quadratic function is

$y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25$

4 0

3 years ago

(x-2)=-1/4(x-8) <br> please show steps

RSB [31]

Answer:

(

−

2

)

=

−

1

4

(

−

8

)

(x-2)=\frac{-1}{4}(x-8)

(x−2)=4−1(x−8)

Solve

1

Eliminate redundant parentheses

(

−

2

)

=

−

1

4

(

−

8

)

−

2

=

−

1

4

(

−

8

)

2

Combine multiplied terms into a single fraction

−

2

=

−

1

4

(

−

8

)

−

2

=

−

1

(

−

8

)

4

3

Distribute

−

2

=

−

1

(

−

8

)

4

−

2

=

−

+

8

4

4

Add

2

2

2

to both sides of the equation

−

2

=

−

+

8

4

−

2

+

2

=

−

+

8

4

+

2

5

Simplify

Add the numbers

=

−

+

8

4

+

2

Solution

=

1

6

5

Step-by-step explanation:

4 0

3 years ago