What value of a is a solution to this equation? 1=3+a 4

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

6 0

Answer:

1=a4+3

Step 1: Subtract a^4+3 from both sides.

1−(a4+3)=a4+3−(a4+3)

−a4−2=0

Step 2: Add 2 to both sides.

−a4−2+2=0+2

−a4=2

Step 3: Divide both sides by -1.

−a4

−1

a4=−2

Step 4: Take root.

a=±(−2)(

)

Answer:

No real solutions.

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Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: $\sqrt{8 - (-1)} = 2(-1)+d$ . On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: $\sqrt{9} = d-2$ . We know that $\sqrt{9}$ = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!