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Sauron [17]
3 years ago
15

Please help!!

Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

The population will be 240,116

Step-by-step explanation:

Exponential growth can be represented by the expression:

P(t) = P_i\,(1+r)^t

where:

P(t) is the population at time (t)

P_i is the initial value of the population

"r" is the annual rate of growth (written in decimal form)

and "t" is the time in years.

Therefore in this situation, P(16) is what we want to find [the population after 16 years]

the initial population P_i is 110,000

the rate of growth is 0.05 [decimal form of 5%]

and t is 16 years.

Replacing all these in the given functional form gives:

P(t) = P_i\,(1+r)^t\\P(16)=110000\,(1+0.05)^16\\P(16)=240116

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Help? i'll mark brainliest if correct
Strike441 [17]

Answer:

36,686

Step-by-step explanation:

5.88 x 12 over 10 = 240

240 x 26 = 36,686

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Pat needs 14 sticks of pepperoni to make 28 pizzas. How many sticks of pepperoni are needed to make 36 pizzas?
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Answer:

18

Step-by-step explanation:

It is 18 because 14 x 2 equal 28 so that would mean you need one stick to make 2 pizzas. Then you divide 36 by 2 and get 18

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Ten minus One-third of a number is 4
zloy xaker [14]
Ok, so you automatically know that you are subtracting 6 from 10 to get 4. So, in order to figure out how it is 1/3 of that number, it is going to be multiplied by 3, getting 18. So, the number would be 18.
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9/11 of a number is 36. What is the number?
mina [271]

Answer:

44

Step-by-step explanation:

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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

n = 100, p = 0.42

92% confidence level

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

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The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

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3 years ago
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