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Kryger [21]
3 years ago
6

What is the opposite of the opposite of -3/8

Mathematics
1 answer:
Komok [63]3 years ago
4 0
The opposite of -3/8 is 3/8 and the opposite of that is -3/8.

The answer is -3/8
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0.000002

Step-by-step explanation:

2* 10^-6

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2 * 0.000001

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0.000002

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Jasjeet and her brother collect stamps.
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Given the sample mean = 21.15, sample standard deviation = 4.7152, and N = 40 for the low income group,Test the claim that the m
miskamm [114]

Answer:

Null hypothesis:

\mathtt{H_o : \mu = 21.21}

Alternative hypothesis

\mathtt{H_1 : \mu \geq 21.21}

t = -0.080

Decision Rule: To  reject the null hypothesis if t > 1.340 at t

Since t = -0.080, this implies that t < 1.340 that means the t statistics value did not fall into the rejection region. Hence, we fail to reject the null hypothesis at the level of significance 0.10

Conclusion: We conclude that there is insufficient evidence to support the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

Step-by-step explanation:

Given that:

the sample mean \overline x = 21.15

the standard deviation \sigma = 4.7512

sample size N = 40

The objective is to test the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

At the level of significance of 0.1

The null hypothesis and the alternative hypothesis for this study can be computed as follows:

Null hypothesis:

\mathtt{H_o : \mu = 21.21}

Alternative hypothesis

\mathtt{H_1 : \mu \geq 21.21}

This test signifies a one-tailed test since the alternative is greater than or equal to 21.21

The t-test statistics can be computed by using the formula:

t= \dfrac{\overline x - \mu  }{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{21.15- 21.21  }{\dfrac{4.7152}{\sqrt{40}}}

t = \dfrac{-0.06  }{\dfrac{4.7152}{6.3246}}

t = -0.080

degree of freedom = n - 1

degree of freedom =  40 - 1

degree of freedom = 39

From the t statistical tables,

at the level of significance ∝ = 0.1 and degree of freedom df = 39, the critical value of \mathtt{{T_{39,0.10} = 1.304}}

Decision Rule: To  reject the null hypothesis if t > 1.340 at t

Since t = -0.080, this implies that t < 1.340 that means the t statistics value did not fall into the rejection region. Hence, we fail to reject the null hypothesis at the level of significance 0.10

Conclusion: We conclude that there is insufficient evidence to support the claim that the mean nickel diameter drawn by children in the low-income group is greater than 21.21 mm.

5 0
3 years ago
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