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3 years ago

There are 10 Pokémon cards on a table. Three are identical Pikachu cards, two are identical Charmander

Mathematics

1 answer:

Amanda [17]3 years ago

7 0

Answer:

These cards can be arranged in 3,628,800 ways.

Step-by-step explanation:

Number of arrangements of n elements:

The number of possible arrangements of n elements is given by:

$A_{n} = n!$

How many different ways can these cards be arranged?

10 cards, so:

$A_{10} = 10! = 3628800$

These cards can be arranged in 3,628,800 ways.

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Urgent help needed algebra 2

blsea [12.9K]

The solution of the given equation (x + 5) - ( 2x - 3) = 6 is 2.

<h3>What is a linear equation?</h3>

A linear equation is an equation that has the variable of the highest power of 1.

The standard form of a linear equation is of the form Ax + B = 0.

The given equation is;

(x + 5) - ( 2x - 3) = 6

To solve;

(x + 5) - ( 2x - 3) = 6

Distribute the negative;

(x + 5) - 2x + 3 = 6

we need to get the like terms together;

x - 2x + 5+ 3 = 6

-x + 8 = 6

Subtract 8 from both sides, we get;

-x = -2

x = 2

Hence, the solution of the given equation is 2.

Learn more about linear equations;

brainly.com/question/10413253

#SPJ1

3 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

A building in the shape of a pyramid was recently built. Each side of the pyramid’s square base has a length of 40 feet and the

Alex

Answer:32,000ft^3

Step-by-step explanation:

3 0

3 years ago

Genetic Inheritance: Calculate probability of two children having the same genotype for achrondoplasia Achondroplasia is a commo

dimaraw [331]

Answer:

The correct answer is - 1/2 or 50% for first and second child to be affected.

Step-by-step explanation:

Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.

A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.

a cross between affected or dwarf and normal parent

Aa X aa

Punnett square:

a a

A Aa Aa

a aa aa

Aa- dwarfness

aa- normal height

The probability that both their first child and second child would have achondroplasia is

2/4 =1/2 or 50%.

6 0

3 years ago

Wich situation can NOT represent a proportional relationship

aliya0001 [1]

Answer:

We need an image or more info

Step-by-step explanation:

8 0

3 years ago