Hmm if I'm not mistaken, is just an "ordinary" annuity, thus
![\bf \qquad \qquad \textit{Future Value of an ordinary annuity} \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right] \\\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7BFuture%20Value%20of%20an%20ordinary%20annuity%7D%0A%5C%5C%5C%5C%0AA%3Dpymnt%5Cleft%5B%20%5Ccfrac%7B%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%20%5Cright%29%5E%7Bnt%7D-1%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D%20%5Cright%5D%0A%5C%5C%5C%5C%5C%5C)
11%
I multiplied the price by percentages up until I got a little over 2.
Answer:
'

Step-by-step explanation:
Given


Required (Missing part of the question)
(a) The marble is red. (b) The marble is odd-numbered
Solving (a): Probability of Red.
This is calculated as:




Solving (b): Probability of Odd
Since each marble type is numbered 1 to 38, then half of it are odd.
i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.
So, the probability of odd is:




Since the amount of coworkers would be the variable in this expression, the equation would be 48-8x
(X= number of coworkers)
<span>Simplifying
fg + -9n = 10j
Solving
fg + -9n = 10j
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Add '9n' to each side of the equation.
fg + -9n + 9n = 10j + 9n
Combine like terms: -9n + 9n = 0
fg + 0 = 10j + 9n
fg = 10j + 9n
Divide each side by 'g'.
f = 10g-1j + 9g-1n
Simplifying
f = 10g-1j + 9g-1n</span>